To solve the equation \(\left(\frac{13}{5}\right)^{x}=4^{x+1}\), we can take the natural logarithm of both sides to simplify the exponents. This will allow us to solve for \(x\) using algebraic manipulation.
Step 1: Take the Natural Logarithm of Both Sides
Given the equation:
\[
\left(\frac{13}{5}\right)^{x} = 4^{x+1}
\]
we take the natural logarithm of both sides:
\[
\ln\left(\left(\frac{13}{5}\right)^{x}\right) = \ln\left(4^{x+1}\right)
\]
Step 2: Apply Logarithm Properties
Using the property \(\ln(a^b) = b \ln(a)\), we get:
\[
x \ln\left(\frac{13}{5}\right) = (x + 1) \ln(4)
\]
Step 3: Distribute and Rearrange
Distribute \(\ln(4)\) on the right-hand side:
\[
x \ln\left(\frac{13}{5}\right) = x \ln(4) + \ln(4)
\]
Rearrange to isolate \(x\):
\[
x \ln\left(\frac{13}{5}\right) - x \ln(4) = \ln(4)
\]
Factor out \(x\):
\[
x \left(\ln\left(\frac{13}{5}\right) - \ln(4)\right) = \ln(4)
\]
Step 4: Solve for \(x\)
Divide both sides by \(\ln\left(\frac{13}{5}\right) - \ln(4)\):
\[
x = \frac{\ln(4)}{\ln\left(\frac{13}{5}\right) - \ln(4)}
\]