Questions: Find the x-values of all points where the function has any relative extrema. Find the value(s) of any relative extrema.
f(x)=-x^2+5x-2
Select the correct choice below and, if necessary, fill in any answer boxes within your choice.
A. The function has a relative maximum of at x= and a relative minimum of at x= 17. (Use a comma to separate answers as needed.)
B. There are no relative maxima. The function has a relative minimum of at x= (Use a comma to separate answers as needed.)
C. There are no relative minima. The function has a relative maximum of at x= 17.
(Use a comma to separate answers as needed.)
D. There are no relative extrema.
Transcript text: Find the $x$-values of all points where the function has any relative extrema. Find the value(s) of any relative extrema.
\[
f(x)=-x^{2}+5 x-2
\]
Select the correct choice below and, if necessary, fill in any answer boxes within your choice.
A. The function has a relative maximum of $\square$ at $x=$ $\square$ and a relative minimum of $\square$ at $x=$ $\square$ 17. (Use a comma to separate answers as needed.)
B. There are no relative maxima. The function has a relative minimum of $\square$ at $x=$ $\square$ (Use a comma to separate answers as needed.)
C. There are no relative minima. The function has a relative maximum of $\square$ at $x=$ $\square$ 17.
(Use a comma to separate answers as needed.)
D. There are no relative extrema.
Solution
Solution Steps
Step 1: Find the derivative of $f(x)$
The derivative of $f(x)$ is $f'(x) = 5 - 2 x$.
Step 2: Solve $f'(x) = 0$
The critical points are found by solving $f'(x) = 0$. The solutions are \left\{\frac{5}{2}\right\}.
Step 3: Determine the nature of each critical point
At $x = \frac{5}{2}$, the function has a relative maximum.
Step 4: Find the value of $f(x)$ at each relative extremum
At $x = \frac{5}{2}$, $f(x) = 4.25$.
Final Answer:
The function has a relative maximum at $x = \frac{5}{2}$, with $f(x) = 4.25$.