Questions: If a is an even positive integer and b is an odd positive integer, then which of the following expressions will NEVER be an integer?

If a is an even positive integer and b is an odd positive integer, then which of the following expressions will NEVER be an integer?
Transcript text: If $a$ is an even positive integer and $b$ is an odd positive integer, then which of the following expressions will NEVER be an integer?
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Solution

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Solution Steps

Step 1: Understand the given conditions
  • a a is an even positive integer, so a=2k a = 2k where k k is a positive integer.
  • b b is an odd positive integer, so b=2m+1 b = 2m + 1 where m m is a non-negative integer.
Step 2: Analyze the properties of even and odd numbers
  • The sum of an even and an odd number is odd: a+b=2k+(2m+1)=2(k+m)+1 a + b = 2k + (2m + 1) = 2(k + m) + 1 , which is odd.
  • The product of an even and an odd number is even: ab=2k(2m+1)=2k(2m+1) a \cdot b = 2k \cdot (2m + 1) = 2k(2m + 1) , which is even.
Step 3: Identify expressions that will never be an integer
  • Since a a is even and b b is odd, expressions like ab \frac{a}{b} or ba \frac{b}{a} may not always be integers. Specifically:
    • ab=2k2m+1 \frac{a}{b} = \frac{2k}{2m + 1} will not be an integer unless 2m+1 2m + 1 divides 2k 2k , which is unlikely for arbitrary k k and m m .
    • ba=2m+12k \frac{b}{a} = \frac{2m + 1}{2k} will not be an integer unless 2k 2k divides 2m+1 2m + 1 , which is impossible since 2k 2k is even and 2m+1 2m + 1 is odd.

Thus, expressions like ab \frac{a}{b} or ba \frac{b}{a} will never be integers under the given conditions.

Final Answer

The expression ba \frac{b}{a} will NEVER be an integer. Thus, the final answer is ba \boxed{\frac{b}{a}} .

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