Questions: If a is an even positive integer and b is an odd positive integer, then which of the following expressions will NEVER be an integer?
Transcript text: If $a$ is an even positive integer and $b$ is an odd positive integer, then which of the following expressions will NEVER be an integer?
Solution
Solution Steps
Step 1: Understand the given conditions
\( a \) is an even positive integer, so \( a = 2k \) where \( k \) is a positive integer.
\( b \) is an odd positive integer, so \( b = 2m + 1 \) where \( m \) is a non-negative integer.
Step 2: Analyze the properties of even and odd numbers
The sum of an even and an odd number is odd: \( a + b = 2k + (2m + 1) = 2(k + m) + 1 \), which is odd.
The product of an even and an odd number is even: \( a \cdot b = 2k \cdot (2m + 1) = 2k(2m + 1) \), which is even.
Step 3: Identify expressions that will never be an integer
Since \( a \) is even and \( b \) is odd, expressions like \( \frac{a}{b} \) or \( \frac{b}{a} \) may not always be integers. Specifically:
\( \frac{a}{b} = \frac{2k}{2m + 1} \) will not be an integer unless \( 2m + 1 \) divides \( 2k \), which is unlikely for arbitrary \( k \) and \( m \).
\( \frac{b}{a} = \frac{2m + 1}{2k} \) will not be an integer unless \( 2k \) divides \( 2m + 1 \), which is impossible since \( 2k \) is even and \( 2m + 1 \) is odd.
Thus, expressions like \( \frac{a}{b} \) or \( \frac{b}{a} \) will never be integers under the given conditions.
Final Answer
The expression \( \frac{b}{a} \) will NEVER be an integer. Thus, the final answer is \( \boxed{\frac{b}{a}} \).