Questions: If h(x)=5+x and k(x)=1/x, which expression is equivalent to (k ∘ h)(x) ? (5+x)/x 1/(5+x) 5+(1/x) 5+(5+x)

If h(x)=5+x and k(x)=1/x, which expression is equivalent to (k ∘ h)(x) ?
(5+x)/x
1/(5+x)
5+(1/x)
5+(5+x)
Transcript text: If $h(x)=5+x$ and $k(x)=\frac{1}{x}$, which expression is equivalent to $(k \circ h)(x)$ ? $\frac{(5+x)}{x}$ $\frac{1}{(5+x)}$ $5+\left(\frac{1}{x}\right)$ $5+(5+x)$
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Solution

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Solution Steps

Step 1: Understand the Composition of Functions

The problem asks for the expression equivalent to \( (k \circ h)(x) \). The notation \( (k \circ h)(x) \) represents the composition of the functions \( k(x) \) and \( h(x) \), which means we need to evaluate \( k(h(x)) \).

Step 2: Evaluate \( h(x) \)

Given \( h(x) = 5 + x \), we substitute \( x \) into this function to get: \[ h(x) = 5 + x \]

Step 3: Substitute \( h(x) \) into \( k(x) \)

Now, substitute \( h(x) = 5 + x \) into \( k(x) = \frac{1}{x} \): \[ k(h(x)) = k(5 + x) = \frac{1}{5 + x} \]

Final Answer

The expression equivalent to \( (k \circ h)(x) \) is: \[ \boxed{\frac{1}{5 + x}} \]

Thus, the correct choice is \(\frac{1}{(5+x)}\).

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