Questions: Use summation notation to express the following calculations. Multiply scores X and Y and then add each product. EXY Sum the scores X and sum the scores Y and then multiply the sums. (ΣX) (ΣY) Subtract X from Y and sum the differences. Σ(Y-X) Sum the X scores. ΣX

Use summation notation to express the following calculations.

Multiply scores X and Y and then add each product.
EXY

Sum the scores X and sum the scores Y and then multiply the sums.
(ΣX) (ΣY)

Subtract X from Y and sum the differences.
Σ(Y-X)

Sum the X scores.
ΣX
Transcript text: Use summation notation to express the following calculations. Multiply scores $X$ and $Y$ and then add each product. $EXY$ Sum the scores $X$ and sum the scores $Y$ and then multiply the sums. $(\Sigma X) (\Sigma Y)$ Subtract $X$ from $Y$ and sum the differences. $\Sigma(Y-X)$ Sum the X scores. $\Sigma X$
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Solution

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Solution Steps

Step 1: Sum of Products

To find the sum of the products of corresponding scores XX and YY, we calculate: i=1nXiYi=14+25+36=4+10+18=32 \sum_{i=1}^{n} X_i Y_i = 1 \cdot 4 + 2 \cdot 5 + 3 \cdot 6 = 4 + 10 + 18 = 32

Step 2: Product of Sums

Next, we compute the sum of the scores in XX and YY separately, and then multiply these sums: i=1nXi=1+2+3=6 \sum_{i=1}^{n} X_i = 1 + 2 + 3 = 6 i=1nYi=4+5+6=15 \sum_{i=1}^{n} Y_i = 4 + 5 + 6 = 15 Thus, the product of the sums is: (i=1nXi)(i=1nYi)=615=90 \left( \sum_{i=1}^{n} X_i \right) \left( \sum_{i=1}^{n} Y_i \right) = 6 \cdot 15 = 90

Step 3: Sum of Differences

Finally, we find the sum of the differences between corresponding scores YY and XX: i=1n(YiXi)=(41)+(52)+(63)=3+3+3=9 \sum_{i=1}^{n} (Y_i - X_i) = (4 - 1) + (5 - 2) + (6 - 3) = 3 + 3 + 3 = 9

Final Answer

  1. Sum of Products: 32 \boxed{32}
  2. Product of Sums: 90 \boxed{90}
  3. Sum of Differences: 9 \boxed{9}
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