Evaluate the limit:
\[
\lim _{x \rightarrow 25} \frac{\sqrt{x}-5}{2x-50}
\]
Simplify the denominator
Factor the denominator:
\[
2x - 50 = 2(x - 25)
\]
Rationalize the numerator
Multiply the numerator and denominator by the conjugate of the numerator:
\[
\frac{\sqrt{x}-5}{2(x-25)} \cdot \frac{\sqrt{x}+5}{\sqrt{x}+5} = \frac{(\sqrt{x}-5)(\sqrt{x}+5)}{2(x-25)(\sqrt{x}+5)}
\]
Simplify the numerator
Use the difference of squares formula:
\[
(\sqrt{x}-5)(\sqrt{x}+5) = x - 25
\]
Cancel common terms
Substitute the simplified numerator and cancel \(x - 25\):
\[
\frac{x - 25}{2(x-25)(\sqrt{x}+5)} = \frac{1}{2(\sqrt{x}+5)}
\]
Evaluate the limit
Substitute \(x = 25\) into the simplified expression:
\[
\frac{1}{2(\sqrt{25}+5)} = \frac{1}{2(5+5)} = \frac{1}{20}
\]
The limit evaluates to:
\[
\boxed{\frac{1}{20}}
\]