Questions: Use the graph of y=q(x) to determine the following limits. Use DNE for "does not exist" when applicable.
a. lim x → 7 q(x)= -1
b. lim x → 7+ q(x)=0
c. lim x → 7 q(x)=DNE
Transcript text: Use the graph of $y=q(x)$ to determine the following limits. Use DNE for "does not exist" when applicable.
a. $\lim _{x \rightarrow 7} q(x)=$ $\square$ $-1$
b. $\lim _{x \rightarrow 7^{+}} q(x)=0$ $\square$
c. $\lim _{x \rightarrow 7} q(x)=D N E$
Solution
Solution Steps
Step 1: Analyze the limit as x approaches 7 from the left.
We observe the graph of \(y = q(x)\) as \(x\) approaches 7 from the left (\(x \rightarrow 7^{-}\)). The value of \(q(x)\) approaches -1. So, \(\lim_{x \rightarrow 7^{-}} q(x) = -1\).
Step 2: Analyze the limit as x approaches 7 from the right.
We observe the graph of \(y = q(x)\) as \(x\) approaches 7 from the right (\(x \rightarrow 7^{+}\)). The value of \(q(x)\) approaches -1. So, \(\lim_{x \rightarrow 7^{+}} q(x) = -1\).
Step 3: Analyze the limit as x approaches 7.
Since \(\lim_{x \rightarrow 7^{-}} q(x) = -1\) and \(\lim_{x \rightarrow 7^{+}} q(x) = -1\), the limit as \(x\) approaches 7 is -1. So, \(\lim_{x \rightarrow 7} q(x) = -1\).
Final Answer
a. \(\boxed{-1}\)
b. \(\boxed{-1}\)
c. \(\boxed{-1}\)