Questions: Use the graph of y=q(x) to determine the following limits. Use DNE for "does not exist" when applicable. a. lim x → 7 q(x)= -1 b. lim x → 7+ q(x)=0 c. lim x → 7 q(x)=DNE

Use the graph of y=q(x) to determine the following limits. Use DNE for "does not exist" when applicable.
a. lim x → 7 q(x)= -1
b. lim x → 7+ q(x)=0
c. lim x → 7 q(x)=DNE
Transcript text: Use the graph of $y=q(x)$ to determine the following limits. Use DNE for "does not exist" when applicable. a. $\lim _{x \rightarrow 7} q(x)=$ $\square$ $-1$ b. $\lim _{x \rightarrow 7^{+}} q(x)=0$ $\square$ c. $\lim _{x \rightarrow 7} q(x)=D N E$
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Solution

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Solution Steps

Step 1: Analyze the limit as x approaches 7 from the left.

We observe the graph of \(y = q(x)\) as \(x\) approaches 7 from the left (\(x \rightarrow 7^{-}\)). The value of \(q(x)\) approaches -1. So, \(\lim_{x \rightarrow 7^{-}} q(x) = -1\).

Step 2: Analyze the limit as x approaches 7 from the right.

We observe the graph of \(y = q(x)\) as \(x\) approaches 7 from the right (\(x \rightarrow 7^{+}\)). The value of \(q(x)\) approaches -1. So, \(\lim_{x \rightarrow 7^{+}} q(x) = -1\).

Step 3: Analyze the limit as x approaches 7.

Since \(\lim_{x \rightarrow 7^{-}} q(x) = -1\) and \(\lim_{x \rightarrow 7^{+}} q(x) = -1\), the limit as \(x\) approaches 7 is -1. So, \(\lim_{x \rightarrow 7} q(x) = -1\).

Final Answer

a. \(\boxed{-1}\) b. \(\boxed{-1}\) c. \(\boxed{-1}\)

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