Questions: a<0 ; b^2-4ac=0

a<0 ; b^2-4ac=0
Transcript text: $a<0 ; b^{2}-4 a c=0$
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Solution

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Solution Steps

To solve the given mathematical conditions, we need to check if the quadratic equation \( b^2 - 4ac = 0 \) holds true and if \( a < 0 \). This involves evaluating the given expressions and verifying the conditions.

Step 1: Verify \( a < 0 \)

Given \( a = -1 \), we need to check if \( a < 0 \).

Since \( -1 < 0 \), the condition \( a < 0 \) is satisfied.

Step 2: Verify \( b^2 - 4ac = 0 \)

Given \( b = 2 \), \( a = -1 \), and \( c = 1 \), we need to check if \( b^2 - 4ac = 0 \).

Calculate \( b^2 - 4ac \): \[ b^2 - 4ac = 2^2 - 4(-1)(1) = 4 + 4 = 8 \]

Since \( 8 \neq 0 \), the condition \( b^2 - 4ac = 0 \) is not satisfied.

Final Answer

\(\boxed{8 \neq 0}\)

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