Questions: F3=400 N vecR-vecF1+vecF2+vecF3 R2=Fr y+F2 y+F3 y=(300 N)left(sin 45^circright)+(200)left(33^circright)+(1001)left(cos 30^circright) Which (if any) terms are missing negative signs here? (check all that apply) F1x F2x F3x F1y F2y F3y

F3=400 N

vecR-vecF1+vecF2+vecF3

R2=Fr y+F2 y+F3 y=(300 N)left(sin 45^circright)+(200)left(33^circright)+(1001)left(cos 30^circright)

Which (if any) terms are missing negative signs here?
(check all that apply)
F1x
F2x
F3x
F1y
F2y
F3y

Transcript text: $F_{3}=400 \mathrm{~N}$ \[ \begin{array}{l} \vec{R}-\vec{F}_{1}+\vec{F}_{2}+\vec{F}_{3} \end{array} \] \[ \begin{array}{l} R_{2}=F_{r y}+F_{2 y}+F_{3 y}=(300 \mathrm{~N})\left(\sin 45^{\circ}\right)+(200)\left(3_{3}^{\circ}\right)+(1001)\left(\cos 30^{\circ}\right) \end{array} \] Which (if any) terms are missing negative signs here? (check all that apply) F1x F2x F3x F1y F2y F3y

Solution

Solution Steps

Step 1: Analyze the given forces and their components.

We are given three forces F1, F2, and F3. F1 has a magnitude of 300N at an angle of 45 degrees above the negative x-axis. F2 has a magnitude of 200N at an angle of 43 degrees below the positive x-axis. F3 has a magnitude of 400N at an angle of 30 degrees below the negative x-axis. We need to find which terms are missing negative signs when calculating the y-component of the resultant force (Ry).

Step 2: Determine the signs of the y-components.