Questions: Solve. 3x^3-x^2+27x-9=0 Write imaginary solutions in terms of i. If there are multiple solutions, separate the answers with commas. x=

Solve.
3x^3-x^2+27x-9=0

Write imaginary solutions in terms of i. If there are multiple solutions, separate the answers with commas. 
x=
Transcript text: Solve. \[ 3 x^{3}-x^{2}+27 x-9=0 \] Write imaginary solutions in terms of $i$. If there are multiple solutions, separate the answers with commas (,). \[ x= \] $\square$
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Solution

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Solution Steps

To solve the cubic equation \(3x^3 - x^2 + 27x - 9 = 0\), we can use numerical methods or a library that handles polynomial equations. The numpy library in Python provides a convenient function to find the roots of a polynomial. We will represent the polynomial with its coefficients and use numpy.roots to find all solutions, including imaginary ones.

Step 1: Identify the Roots of the Polynomial

The roots of the polynomial \(3x^3 - x^2 + 27x - 9 = 0\) are calculated as follows:

  • \(x_1 = 3.8257 \times 10^{-18} + 3i\)
  • \(x_2 = 3.8257 \times 10^{-18} - 3i\)
  • \(x_3 = 0.3333\)
Step 2: Interpret the Roots

The roots include two complex conjugate pairs and one real root:

  • The complex roots are \(x_1 = 3i\) and \(x_2 = -3i\).
  • The real root is \(x_3 = \frac{1}{3}\).

Final Answer

The solutions to the equation \(3x^3 - x^2 + 27x - 9 = 0\) are: \[ \boxed{x = 3i, -3i, \frac{1}{3}} \]

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