The function \( L(T) \) is:
\[ L = 0.8125T^2 \]
For \( T = 17 \) seconds:
\[ L = 0.8125(17^2) \]
\[ L = 0.8125 \times 289 \]
\[ L = 234.0625 \text{ feet} \]
For \( L = 11 \) inches (convert to feet: \( \frac{11}{12} \) feet):
\[ \frac{11}{12} = 0.8125T^2 \]
\[ T^2 = \frac{11}{12 \times 0.8125} \]
\[ T^2 = \frac{11}{9.75} \]
\[ T^2 = 1.1282 \]
\[ T = \sqrt{1.1282} \]
\[ T \approx 1.0622 \text{ seconds} \]
(a) The function \( L(T) \) is:
\[ L = 0.8125T^2 \]
(b) The length of the Foucault pendulum is:
\[ 234.0625 \text{ feet} \]
(c) The period of the hypnotist's pendulum is:
\[ 1.0622 \text{ seconds} \]
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