Questions: For the functions w=xy+yz+xz, x=3u+v, y=3u-v, and z=uv, express the partial derivative of w with respect to u and the partial derivative of w with respect to v using the chain rule and by expressing w directly in terms of u and v before differentiating. Then evaluate the partial derivative of w with respect to u and the partial derivative of w with respect to v at the point (u, v)=(-1/4, 3).
Express the partial derivative of w with respect to u and the partial derivative of w with respect to v as functions of u and v.
Transcript text: For the functions $w=x y+y z+x z, x=3 u+v, y=3 u-v$, and $z=u v$, express $\frac{\partial w}{\partial u}$ and $\frac{\partial w}{\partial v}$ using the chain rule and by expressing $w$ directly in terms of $u$ and $v$ before differentiating. Then evaluate $\frac{\partial w}{\partial u}$ and $\frac{\partial \mathrm{w}}{\partial \mathrm{v}}$ at the point $(u, v)=\left(-\frac{1}{4}, 3\right)$.
Express $\frac{\partial w}{\partial u}$ and $\frac{\partial w}{\partial v}$ as functions of $u$ and $v$.
Solution
Solution Steps
To solve this problem, we need to use the chain rule to express the partial derivatives of \( w \) with respect to \( u \) and \( v \). First, substitute the expressions for \( x \), \( y \), and \( z \) in terms of \( u \) and \( v \) into the function \( w \). Then, differentiate the resulting expression for \( w \) with respect to \( u \) and \( v \). Finally, evaluate these derivatives at the given point \((u, v) = \left(-\frac{1}{4}, 3\right)\).
Step 1: Express \( w \) in Terms of \( u \) and \( v \)
Given the functions:
\( x = 3u + v \)
\( y = 3u - v \)
\( z = uv \)
The function \( w \) is defined as:
\[ w = xy + yz + xz \]
Substituting the expressions for \( x \), \( y \), and \( z \) into \( w \):
\[ w = (3u + v)(3u - v) + (3u - v)(uv) + (3u + v)(uv) \]