Questions: A data set includes weights (in grams) of 36 Reese's Peanut Butter Cup Miniatures. The accompanying Statdisk display shows results from using all 36 weights to test the claim that the sample is from a population with a mean equal to 8.953 g. Test the given claim by using the display provided from Statdisk. Use a 0.01 significance level.
Identify the null and alternative hypotheses.
Transcript text: A data set includes weights (in grams) of 36 Reese's Peanut Butter Cup Miniatures. The accompanying Statdisk display shows results from using all 36 weights to test the claim that the sample is from a population with a mean equal to 8.953 g . Test the given claim by using the display provided from Statdisk. Use a 0.01 significance level.
Identify the null and alternative hypotheses.
$\mathrm{H}_{0}$ : $\square$
$\square$
$\square$
$\mathrm{H}_{1}$ : $\square$
$\square$
$\square$
Solution
Solution Steps
Step 1: Define Hypotheses
We are testing the claim that the sample is from a population with a mean equal to μ0=8.953g. The null and alternative hypotheses are defined as follows:
H0:μ=8.953H1:μ=8.953
Step 2: Calculate Standard Error
The standard error SE is calculated using the formula:
SE=nσ=360.132=0.022
Step 3: Calculate Test Statistic
The test statistic Ztest is calculated using the formula:
Ztest=SExˉ−μ0=0.0228.941−8.953=−0.5455
Step 4: Calculate P-value
For a two-tailed test, the p-value P is calculated as:
P=2×(1−T(∣z∣))=0.5854
Step 5: Decision Rule
We compare the p-value to the significance level α=0.01:
If P<α, we reject the null hypothesis.
If P≥α, we fail to reject the null hypothesis.
In this case:
0.5854≥0.01
Step 6: Conclusion
Since the p-value is greater than the significance level, we fail to reject the null hypothesis.
Final Answer
The conclusion is that there is not enough evidence to reject the claim that the sample is from a population with a mean equal to 8.953g.