\[ -3x + 3 - 3 \leq 18 - 3 \] \[ -3x \leq 15 \]
\[ \frac{-3x}{-3} \geq \frac{15}{-3} \] \[ x \geq -5 \]
The solution set is all real numbers \( x \) such that \( x \geq -5 \). In interval notation, this is written as: \[ [-5, \infty) \]
\(\boxed{[-5, \infty)}\)
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