Questions: The expression
[
left(frac2 a^-65 b^-1 / 2right)^-1
]
equals (n a^r / b^t) where
n , the coefficient, is:
(r), the exponent of (a), is:
(t), the exponent of (b), is:
Transcript text: The expression
\[
\left(\frac{2 a^{-6}}{5 b^{-1 / 2}}\right)^{-1}
\]
equals $n a^{r} / b^{t}$ where
n , the coefficient, is: $\square$
$r$, the exponent of $a$, is: $\square$
$t$, the exponent of $b$, is: $\square$
Solution
Solution Steps
Step 1: Rewrite the expression using the negative exponent rule
The given expression is:
\[
\left(\frac{2 a^{-6}}{5 b^{-1 / 2}}\right)^{-1}
\]
Using the rule \( \left(\frac{x}{y}\right)^{-1} = \frac{y}{x} \), we rewrite the expression as:
\[
\frac{5 b^{-1 / 2}}{2 a^{-6}}
\]
Step 2: Simplify the exponents of \( a \) and \( b \)
Using the rule \( x^{-n} = \frac{1}{x^n} \), we rewrite the expression as:
\[
\frac{5 \cdot \frac{1}{b^{1/2}}}{2 \cdot \frac{1}{a^6}}
\]
This simplifies to:
\[
\frac{5}{2} \cdot \frac{a^6}{b^{1/2}}
\]
Step 3: Express the result in the form \( \frac{n a^r}{b^t} \)
The expression is now in the form:
\[
\frac{5}{2} \cdot \frac{a^6}{b^{1/2}} = \frac{5 a^6}{2 b^{1/2}}
\]
Thus:
\( n = \frac{5}{2} \)
\( r = 6 \)
\( t = \frac{1}{2} \)
Final Answer
\( n = \frac{5}{2} \) \\
\( r = 6 \) \\
\( t = \frac{1}{2} \)
Thus, the final boxed answers are:
\[
\boxed{n = \frac{5}{2}} \\
\boxed{r = 6} \\
\boxed{t = \frac{1}{2}}
\]