Since \( \triangle QRS \) is a right triangle at \( S \), we can use the Pythagorean theorem: \[ QR^2 = QS^2 + RS^2 \]
Since \( QT = 45 \) and \( ST = 8u \), we can express \( QS \) as: \[ QS = QT - ST = 45 - 8u \]
Substitute \( QR = 45 \), \( QS = 45 - 8u \), and \( RS = u + 42 \) into the Pythagorean theorem: \[ 45^2 = (45 - 8u)^2 + (u + 42)^2 \]
\[ 2025 = (45 - 8u)^2 + (u + 42)^2 \] \[ 2025 = (2025 - 720u + 64u^2) + (u^2 + 84u + 1764) \] \[ 2025 = 65u^2 - 636u + 3789 \]
\[ 0 = 65u^2 - 636u + 1764 \] Use the quadratic formula \( u = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a} \): \[ a = 65, b = -636, c = 1764 \] \[ u = \frac{636 \pm \sqrt{636^2 - 4 \cdot 65 \cdot 1764}}{2 \cdot 65} \] \[ u = \frac{636 \pm \sqrt{404496 - 458640}}{130} \] \[ u = \frac{636 \pm \sqrt{-54144}}{130} \]
Since the discriminant is negative, there is no real solution for \( u \). Therefore, we need to recheck the problem setup or calculations.
There is no real value for \( u \) that satisfies the given conditions.
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