Questions: Given the joint probability table above what is P[Not A B]? .50 .25 .75 .56

Given the joint probability table above what is P[Not A  B]?
.50
.25
.75
.56
Transcript text: \begin{tabular}{|l|l|l|l|} \hline & A & Not A & \\ \hline B & .15 & .05 & .20 \\ \hline Not B & .15 & .65 & .80 \\ \hline & .30 & .70 & 1.00 \\ \hline \end{tabular} Given the joint probability table above what is $\mathrm{P}[\operatorname{Not} \mathrm{A} \mid \mathrm{B}]$ ? .50 .25 .75 .56
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Solution

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Given the joint probability table, calculate \( \mathrm{P}[\operatorname{Not} \mathrm{A} \mid \mathrm{B}] \).

Identify the relevant probabilities from the table.

From the table:

  • \( \mathrm{P}(B) = 0.20 \)
  • \( \mathrm{P}(\operatorname{Not} A \cap B) = 0.05 \)

The probability \( \mathrm{P}[\operatorname{Not} \mathrm{A} \mid \mathrm{B}] \) is calculated as: \[ \mathrm{P}[\operatorname{Not} \mathrm{A} \mid \mathrm{B}] = \frac{\mathrm{P}(\operatorname{Not} A \cap B)}{\mathrm{P}(B)} = \frac{0.05}{0.20} = 0.25 \] \[ \boxed{0.25} \]

The probability \( \mathrm{P}[\operatorname{Not} \mathrm{A} \mid \mathrm{B}] \) is \boxed{0.25}.

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