Questions: Fill in the name and empirical formula of each ionic compound that could be formed from the ions Some ionic compounds name of compound cation anion empirical formula Lead Periodate Pb^2+ IO4^- Pb(IO4)2 Mg^2+ CO3^2- MgCO3 magnesium carbonate Fe^3+ ClO3^-

Fill in the name and empirical formula of each ionic compound that could be formed from the ions Some ionic compounds name of compound cation anion empirical formula Lead Periodate Pb^2+ IO4^- Pb(IO4)2 Mg^2+ CO3^2- MgCO3 magnesium carbonate Fe^3+ ClO3^-
Transcript text: Fill in the name and empirical formula of each ionic compound that could be formed from the ions \begin{tabular}{|c|c|c|c|} \hline \multicolumn{3}{|c|}{ Some ionic compounds } & name of compound \\ \hline cation & anion & empirical formula & Lead Periodate \\ \hline $\mathrm{Pb}^{2+}$ & $\mathrm{IO}_{4}^{-}$ & $\mathrm{Pb}\left(\mathrm{IO}_{4}\right)_{2}$ & \\ \hline $\mathrm{Mg}^{2+}$ & $\mathrm{CO}_{3}^{2-}$ & $\mathrm{MgCO}_{3}$ & magnesium carbonate \\ \hline $\mathrm{Fe}^{3+}$ & $\mathrm{ClO}_{3}^{-}$ & $\square$ \\ \hline \end{tabular}
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Solution

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Solution Steps

Step 1: Identify the cation and anion for the missing compound

The missing compound involves the cation \(\mathrm{Fe}^{3+}\) and the anion \(\mathrm{ClO}_{3}^{-}\).

Step 2: Determine the empirical formula

To form a neutral ionic compound, the total positive charge must equal the total negative charge. The cation \(\mathrm{Fe}^{3+}\) has a charge of \(+3\), and the anion \(\mathrm{ClO}_{3}^{-}\) has a charge of \(-1\). Therefore, we need three \(\mathrm{ClO}_{3}^{-}\) anions to balance one \(\mathrm{Fe}^{3+}\) cation.

The empirical formula is: \[ \mathrm{Fe(ClO}_{3}\mathrm{)}_{3} \]

Step 3: Name the compound

The compound formed by \(\mathrm{Fe}^{3+}\) and \(\mathrm{ClO}_{3}^{-}\) is named iron(III) chlorate.

Final Answer

\[ \boxed{\mathrm{Fe(ClO}_{3}\mathrm{)}_{3}} \] The name of the compound is iron(III) chlorate.

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