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As shown in the figure below, we have a square one meter on a side that is free to rotate about an axis perpendicular to the plane of the square, a distance a from one side and a distance b from the other side. Two forces, F1 and F2, are applied to diagonally opposite comers, and act along the sides of the square, first as shown in case (i) and then as shown in case (ii) of the drawing. In each case the net torque produced by the forces is zero. If the magnitude of F2 is 6 times that of F1, find the distances a and b that locate the axis. It should be noted that a and b are not drawn to scale. a= Since we need to calculate torques, see if you can write an expression for the torque in terms of the force producing that torque and the perpendicular distance between the line of action of the force and the point about which we wish to determine the torque. After equating the clockwise to the counterclockwise torques for each case and inserting the relationship between the magnitude of the forces, we have two equations and two unknowns (σ and b). To determine the value for a, see if you can manipulate these two equations in such a manner as to eliminate b and allow you to solve for a. b= Similar to your calculation of a, after equating the clockwise to the counterclockwise torques for each case and inserting the relationship between the magnitude of the forces, we have two equations and two unknowns (α and b). To determine the value for b, see if you can manipulate these two equations in such a manner as to eliminate a and allow you to solve for b.