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R3. The battery supplies a constant voltage Vb, and the resistors are labeled with their resistances. The ammeters are ideal meters that read I1 and I2 respectively. The direction of each loop and the direction of each current arrow that you draw on your own circuits are arbitrary. Just assign voltage drops consistently and sum both voltage drops and currents algebraically and you will get correct equations. If the actual current is in the opposite direction from your current arrow, your answer for that current will be negative. The direction of any loop is even less important The equation obtained from a counterclockwise loop is the same as that from a clockwise loop except for a negative sign in front of every term (i.e., an inconsequential change in overall sign of the equation because it equals zero). Apply the junction rule to the junction labeled with the number 1 (at the bottom of the resistor of resistance R2). Answer in terms of given quantities, together with the meter readings I1 and I2 and the current I3. Sigma I=0=I3+I2-I1 You have indicated that I1 and I2 flow into the junction and I3 flows out. Is this what the diagram shows? If you apply the junction rule to the junction above R2, you should find that the expression you get is equivalent to what you just obtained for the junction labeled 1. Obviously the conservation of charge or current flow enforces the same relationship among the currents when they separate as when they recombine. Apply the loop rule to loop 2 (the smaller loop on the right). Sum the voltage changes across each circuit element around this loop going in the direction of the arrow. Remember that the current meter is ideal. Express the voltage drops in terms of Vb, I2, I3, the given resistances, and any other given quantities.
Fifty-four wild bears were anesthetized, and then their weights and chest sizes were measured and listed in a data set. Results are shown in the accompanying display. Is there sufficient evidence to support the claim that there is a linear correlation between the weights of bears and their chest sizes? When measuring an anesthetized bear, is it easier to measure chest size than weight? If so, does it appear that a measured chest size can be used to predict the weight? Use a significance level of α=0.05. Determine the null and alternative hypotheses. H0: p=□ H1: ρ> Identify the correlation coefficient, r. r= □ Identify the critical value(s). A. There are two critical values at r= ± □ B. There is one critical value at r= □ Is there sufficient evidence to support the claim that there is a linear correlation between the weights of bears and their chest sizes? Choose the correct answer below and, if necessary, fill in the answer box within your choice. A. Yes, because the correlation coefficient □ falls outside the critical value(s). B. No, because the correlation coefficient □ falls outside the critical value(s). C. No, because the correlation coefficient □ falls between the critical values. D. Yes, because the correlation coefficient □ falls between the critical values. E. The answer cannot be determined from the given information. When measuring an anesthetized bear, is it easier to measure chest size than weight? If so, does it appear that a measured chest size can be used to predict the weight? A. Yes, it is easier to measure a chest size than a weight because measuring weight would require lifting the bear onto the scale. The chest size could not be used to predict weight because there is not a linear correlation between the two. B. Yes, it is easier to measure a chest size than a weight because measuring weight would require lifting the bear onto the scale. The chest size could be used to predict weight because there is a linear correlation between the two. C. No, it is easier to measure weight than chest size because the chest is not a flat surface. D. Yes, it is easier to measure a chest size than a weight because measuring weight would require lifting the bear onto the scale. The chest size could not be used to predict weight because there is too much variance in the weight of the bears.