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The TTC has set a bus mechanical reliability goal of 3,900 bus miles. Bus mechanical reliability is measured specifically as the number of bus miles between mechanical road calls. Suppose a sample of 100 buses resulted in a sample mean of 3,950 bus miles and a sample standard deviation of 175 bus miles. Complete parts (a) and (b) below. a. Is there evidence that the population mean bus miles is more than 3,900 bus miles? (Use a 0.05 level of significance.) State the null and alternative hypotheses. H0: μ = T H1: μ ≠ T (Type integers) Find the test statistic for this hypothesis test. The test statistic t= (Round to two decimal places as needed.) The critical value for the test statistic is(are) . (Round to two decimal places as needed) Is there sufficient evidence to reject the null hypothesis using α=0.05 ? A. Do not reject the null hypothesis. There is insufficient evidence at the 0.05 level of significance that the population mean bus miles is less than 3,900 bus miles. B. Reject the null hypothesis. There is sufficient evidence at the 0.05 level of significance that the population mean bus miles is greater than 3,900 bus miles. C. Reject the null hypothesis. There is sufficient evidence at the 0.05 level of significance that the population mean bus miles is less than 3,900 bus miles. D. Do not reject the null hypothesis. There is insufficient evidence at the 0.05 level of significance that the population mean bus miles is greater than 3,900 bus miles. b. The p-value is . (Round to 3 decimal places as needed.) What does this p-value mean given the results of part (a)? A. The p-value is the probability of getting a sample mean of 3,950 bus miles or greater if the actual mean is 3,900 bus miles. B. The p-value is the probability that the actual mean is 3,950 bus miles or less. C. The p-value is the probability that the actual mean is 3,900 bus miles or greater given the sample mean is 3,950 bus miles.
Determine whether the statement makes sense or does not make sense, and explain your reasoning. I can solve x/9=4/6 by using the cross-products principle or by multiplying both sides by 18, the least common denominator. Choose the correct answer below. A. The statement does not make sense. Multiplying the terms on both sides of the equation by the least common denominator will eliminate the fractions in the equation. However, the value of the missing quantity in a proportion cannot be found by using the cross-products principle if only three of the numbers are known. B. The statement makes sense. If three of the numbers in a proportion are known, the value of the missing quantity can be found by using the cross-products principle. Alternatively, multiplying the terms on both sides of the equation by the least common denominator will eliminate the fractions in the equation. C. The statement does not make sense. If three of the numbers in a proportion are known, the value of the missing quantity can be found by using the cross-products principle. However, the terms on both sides of the equation would need to be multiplied by 6 * 4=24, and not 18, to eliminate the fractions in the equation. D. The statement makes sense. If two of the numbers in a proportion are known, the value of the missing quantities can be found by using the cross-products principle. Alternatively, multiplying the terms on both sides of the equation by the least common denominator will eliminate the fractions in the equation.